Howdy!

I have a component (LED) that has 4 pins internally connected as 2 pairs of pins. Anode (A) = pin 2 & 3; Cathode (K) = pin 1 & 4. I've drawn the pattern and the component.

The problem I have is in the Pin Manager. I can specify "K" = 1 and "K" = 4 and "A" = 2 and "A" = 3, but that gives me extra NETs on a schematic unless I wire the (internally) common pins together on the schematic with a jumper. I would like to make the connection to either common pin while building the PCB without having to remember whether I should create a physical jumper there or not.

Is it possible to get DT to recognize this component's internal jumper?

Regards,

Tex

Hey Tex,

I am not sure, if that is what you need.
If you want to connect two "same" pins as "jumper" in the component, you can define it in the library.

Go to the Component Editor, choose your component. Then open Pattern. In the window you will see the schematic symbol and footprint for the pcb. Now klick on the footprints Anode Pin 2 and then on the Anode Pin 3, now they are connected and you don't need to remember about this connection anymore.

Stefan

Thanks, Stefan, but that would put a trace on the PCB when I place the component pattern.

The "jumper" is already built into the part. Putting the trace on the board does things like block a valuable pathway for another trace. If I don't need to do that, I would prefer that DT recognize that pin 2 & 3 are connected internally. Same with 1 & 4.

oh, ok!

I do it usually with a bigger pads, so that they overlay over each other.

?

You can connect each pin of the component to two pads in Component editor. When you attach pattern to the component, create one connection from pin to pad as usual (for example, from pin A to pad 2), then drag additional connection from pad 2 to pad 3. In the same way, you can link cathode to two pads 1 and 4.

In Component Editor / Attached Pattern, my component has numbered pins (1,2,3,4). I've attached a pattern that has numbered pins (1,2,3,4).

Component Editor shows the Connection List with all four of these pins connected to their patter counterpart (1-1, 2-2, 3-3, 4-4).

I draw a connection on the pattern between the internally jumpered pins (1-4, 2-3).

I place the component in Schematic Editor two times.

I wire pin 1 [cathode (1 & 4)] of the first one to pin 2 [anode (2 & 3)] of the second one.

Instead of those being one NET, they are two different NETs even with the pattern jumpered as you suggested.

See what I mean?

It would be great if you could show picture or send schematic file.

A simple schematic is attached with 3 of these components in series. The pattern is simply 4 pads in a square array.

The only problem I can see is need to create redundant traces between pads 1,4 and 2,3 in spite of these pads are internally connected. If you don't do it, your circuit will work, but checking net connectivity will report you errors (which you can ignore). I don't think it is big problem.